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Old 01-27-2010, 09:47 AM   #1 (permalink)
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Organic Chemistry Halp

I know some of you guys are organic chem wizards.

I am taking orgo2 and it is moving extremely fast and I took orgo1 2 years ago and i remember nothing.

I am probably going to look into getting a tutor or some other form of help but right now I have a quiz due tonight that I am totally clueless about and i wont be able to find any help that fast (the class only started 3 days ago and they did not teach what is on the quiz)

Can anyone help me figure out some pretty basic synthesis but more importantly explain step by step the thought process that goes into the answer?

Here is the first question:

Predict the major Br monosubstituion product of this reaction.
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Old 01-27-2010, 10:16 AM   #2 (permalink)
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i don't see a reaction

Br synthesis major products is whatever side of the bond is less substituted. unless selective reagents are used (ie: LiBr vs Cu2Br). Br is big, polarizable and fuzzy.

i hope this helps

edit: also this is assuming you are using 1equivalent of bromine
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Old 01-27-2010, 10:40 AM   #3 (permalink)
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Quote:
Originally Posted by Captain Cannabis View Post
i don't see a reaction

Br synthesis major products is whatever side of the bond is less substituted. unless selective reagents are used (ie: LiBr vs Cu2Br). Br is big, polarizable and fuzzy.

i hope this helps

edit: also this is assuming you are using 1equivalent of bromine
hmmm thats wierd the picture was showing up for me when i first posted it, ah i think its because i closed the website which the quiz is temporarily hosted on... this should work

first off what do you mean by "substituted"?



the next question is the same except with this reaction



how is this different and why
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Old 01-27-2010, 10:43 AM   #4 (permalink)
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https := secure http

passwords etc. take a screenshot or just describe it with words
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Old 01-27-2010, 11:00 AM   #5 (permalink)
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can you still not see thie pictures? ok ill take a screenshot, BRB
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Old 01-27-2010, 11:02 AM   #6 (permalink)
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my license for chemdraw expired. weakass paint drawings will follow while i try and renew it
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Old 01-27-2010, 11:03 AM   #7 (permalink)
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try marvinsketch, its what we use in my class and i think its free , also thanks much in advance you are greatly helping me

the drawing dont even need to be that good nor do you need to spend time drawing it, if you can explain using words that can also help me. i have a textbook next to me that i am skimming through i just honestly dont know where to start.
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Old 01-27-2010, 11:11 AM   #8 (permalink)
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the first rxn favours allylic substitution because of the resonance stability of the intermediate. draw mechanism if you need to understand this better. it is a free radical chain rxn with 3 steps. the intermediate is favoured because the charge is displaced through the ring ONLY when Br is in that one spot.
edit: the minor product of this reaction is a disubstitution at the same carbon atom

the second reaction favours the substitution on the end of the molecule due mostly to steric hinderance. stereochemical control of this reaction can be acheived with low temperatures 1equivalent of Br in reasonable yeild.
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Old 01-27-2010, 11:15 AM   #9 (permalink)
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Awesome, that helped me alot... I will inevitably have more questions but i have to ponder my book for a while

by the way how do you go about naming a hexane with 3 double bonds and an ethyl group?
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Old 01-27-2010, 11:19 AM   #10 (permalink)
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same way you name anything

find the longest chain and then start at the end with the biggest (heaviest) groups.

so a hexane with an ethyl group can take names like this:
2-ethyl-hexa-1,3,5-ene

i tried to draw a picture but without chemdraw its a waste of time
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Old 01-27-2010, 11:24 AM   #11 (permalink)
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ah ok you just locate the double bonds and add an -ene ending. i see

Predict the major Br monosubstituion product of this reaction.


in this one would the Br go next to the double bond (the 3rd carbon) for the same reason as the first problem? What does NBS stand for?
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Old 01-27-2010, 11:27 AM   #12 (permalink)
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you have to be careful when you have an ethyl near the end because it can make a good 7carbon chain and your most-technically-correct name becomes something stupid like septa-2,4,6-ene or something

naming is stupid
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Old 01-27-2010, 01:36 PM   #13 (permalink)
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what does it mean "substituted groups"?
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Old 01-27-2010, 02:29 PM   #14 (permalink)
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NBS is nbromosuccinimide. It easily and affordably adds one mol eqv of bromine. You are right (sort of) that it will substitute on the 3 carbon as a MAJOR product(because of the allylic stability). Keep in mind there will be trace amounts of 1 substituted monobrominated products as well that need to be removed via purification.
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Old 01-27-2010, 03:39 PM   #15 (permalink)
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wat
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further forward
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Old 01-27-2010, 04:04 PM   #16 (permalink)
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come on keep up, this is basic stuff
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Old 01-28-2010, 05:43 AM   #17 (permalink)
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shit... which one of you can I pay to take the finite math i've been putting off for the past 3 years
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Old 01-28-2010, 08:20 AM   #18 (permalink)
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Quote:
Originally Posted by Captain Cannabis View Post
you have to be careful when you have an ethyl near the end because it can make a good 7carbon chain and your most-technically-correct name becomes something stupid like septa-2,4,6-ene or something

naming is stupid
Blame those IUPAC fuddy duddies
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